HTTPAPI - Error parsing user/password from URL

tools400dev — Tue, 11 Aug 2026 06:15:23 GMT

HTTPAPI does not correctly parse the user and password from a URL, such as "http://userassword@10.212.66.112:8080/auth/basic/".

The problem is the '@', which is a variant character and which has a different hex code on German systems.

I am not sure whether it is the best option, but I made it working on your IBM i by updating procedure http_long_ParseURL() as shown below:

Added:

Code:

      // Define variant character @
     D AT              s              1C   inz(u'0040')

Updated:

Code:

     C* find the last @ symbol in the host name.  It's important
     C* to use the last one, in case the userid is an e-mail address.
     C* for example:
     c*  http://bob@nospam.com:bigboy@www.scottklement.com
     c                   eval      wwPos = 0
     c                   eval      wwFound = %scan(AT: peHost) // Updated
     c                   dow       wwFound > 1 and wwFound < %size(peHost)
     c                   eval      wwPos = wwFound
     c                   eval      wwFound = %scan(AT: peHost: wwFound+1) // Updated
     c                   enddo

Regards,

Thomas.

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HTTPAPI - Error parsing user/password from URL